Implicit Differentiation Calculator
Calculate dy/dx for implicit equations F(x,y)=0 using numerical partial derivatives: dy/dx = −Fₓ/F_y. Includes tangent line, normal line, second derivative d²y/dx², and common curve presets.
dy/dx at (x₀,y₀)
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Tangent line equation —
∂F/∂x (numerical) —
∂F/∂y (numerical) —
Extended More scenarios, charts & detailed breakdown ▾
dy/dx
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Tangent line —
Professional Full parameters & maximum detail ▾
Derivatives
dy/dx —
d²y/dx² —
Lines
Normal line —
Vertical tangent check —
How to Use This Calculator
- Enter F(x,y) set equal to zero (e.g. x^2+y^2-25 for the unit circle).
- Enter the point (x₀, y₀).
- Get dy/dx, the tangent line equation, and partial derivatives Fₓ, F_y.
- Use Common Curves tab for circle, ellipse, and hyperbola presets.
- The Professional tab adds d²y/dx² and normal line.
Formula
dy/dx = −Fₓ/F_y | Fₓ = ∂F/∂x, F_y = ∂F/∂y (numerical)
Example
x²+y²=25, point (3,4): Fₓ=2x=6, F_y=2y=8; dy/dx=−6/8=−0.75. Tangent: y−4=−0.75(x−3).
Frequently Asked Questions
- Implicit differentiation finds dy/dx when y is defined implicitly by F(x,y)=0. Differentiate both sides with respect to x (treating y as a function of x), then solve for dy/dx.
- By the implicit function theorem: dy/dx = −(∂F/∂x)/(∂F/∂y) = −Fₓ/F_y, provided F_y ≠ 0. This is the quickest formula when F(x,y) is given explicitly.
- For x²+y²=r², dy/dx = −x/y. At point (x₀,y₀): tangent line is y−y₀ = (−x₀/y₀)(x−x₀), or equivalently x₀x + y₀y = r².
- A vertical tangent occurs when F_y = ∂F/∂y = 0 at the point (but F_x ≠ 0). The slope dy/dx is undefined there.
- d²y/dx² = −(Fₓₓ·F_y² − 2Fₓᵧ·Fₓ·F_y + F_yy·Fₓ²)/F_y³. Our Professional tab computes this numerically.
Related Calculators
Sources & References (5) ▾
- Implicit Differentiation — Paul's Online Math Notes — Lamar University
- MIT OCW 18.01 — Implicit Differentiation — MIT OpenCourseWare
- Stewart's Calculus — Implicit Differentiation — Cengage / Stewart
- Implicit Differentiation — Khan Academy — Khan Academy
- OpenStax Calculus Vol. 1 — Ch. 3.8 — OpenStax